Respuesta :

toporc
Let [tex] tan^{-1} x=\alpha[/tex]
Then it can be shown by using a right-angled triangle and the rule of Pythagoras that [tex]\alpha= tan^{-1} \frac{x}{ \sqrt{1-x^{2}} }[/tex]
Therefore
[tex]tan(sin ^{-1} (x))=\frac{x}{ \sqrt{1-x^{2}} }[/tex]

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