we know that
The vertex form of a quadratic function is
y=a(x-h)²+k
the vertex is the point (-3,-2)
so
(h,k)--------> (-3,-2)
y=a(x+3)²-2
where a=1
y=(x+3)²-2
Now we can convert this into the standard form of a quadratic equation,
y = ax² + bx + c
y=(x+3)²-2-----> y=x²+6x+9-2-----> y=x²+6x+7
where a =1, b = 6, c = 7the answer isy=x²+6x+7
