kaczmarekr4 kaczmarekr4
  • 13-08-2014
  • Mathematics
contestada

what is the correct definition for tan 0
tan0=1/sin0
tan0=1/cos0
tan0=cos0/sin0
tan0=sin0/cos0
please explain if possible.

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Аноним Аноним
  • 17-08-2014
[tex]tan\theta=\frac{sin\theta}{cos\theta}\\\\\\Look\ at\ the\ picture.\\\\In\ a\ right\ triangle:\\\\sin\theta=\frac{a}{c};\ cos\theta=\frac{b}{c};\ tan\theta=\frac{a}{b}\\\\\frac{sin\theta}{cos\theta}=\frac{\frac{a}{c}}{\frac{b}{c}}=\frac{a}{c}\times\frac{c}{b}=\frac{a}{b}=tan\theta[/tex]
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