730jordayn
730jordayn
12-03-2018
Mathematics
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Where is tge vertex of the graph of y=-x^2
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jdoe0001
jdoe0001
12-03-2018
[tex]\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \boxed{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k})\\\\ -------------------------------\\\\ y=-x^2\implies y=-1(x-\stackrel{h}{0})^2+\stackrel{k}{0}[/tex]
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