To solve this set it equal to 0 [tex]0 = {x}^{2} + 43x + 120[/tex] Now factor [tex]0 = (x + 40)(x + 3)[/tex] Set each side to 0 and solve [tex]x + 40 = 0 \\ x = - 40 \\ x + 3 = 0 \\ x = - 3[/tex] So the zeros (where it crosses the x axis) are [tex]x = - 40 \\ x = - 3[/tex]
