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Solve for x: 2|x āˆ’ 3| + 1 = 7

A x = 0, x = 6
B x = āˆ’1, x = 6
C x = 0, x = 9
D No solutions

Respuesta :

2|x - 3| = 7 - 1
2|x - 3| = 6
|x - 3| = 6/2
|x - 3| = 3
-(x - 3) = 3 and x - 3 = 3
6, 0

Answer: A).
fionahoxha261
Solving for x:

2|x-3|+1=7
Move constant to the right
2|x-3|=7-1
Substarct the numbers
2|x-3|=6
Divide both sides by 2
|x-3|=3
Split into possible cases
x-3=3
x-3=-3

The answer is A x=6
x=0

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