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13-07-2017
Mathematics

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A cylinder has its height doubled and its radius cut to one third. What is the ratio of the volumes of the modified cylinder to the original cylinder?

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egenriether egenriether

13-07-2017

[tex]V_{1} = h_{1}\pi r^{2} [/tex]

[tex]V_{2}=2h_{1} \pi ( \frac{1}{3} r_{1})^{2}=\frac{2}{9} \pi h_{1}( r_{1})^{2}[/tex]

Taking the ratio of V2/V1 = 2/9

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