mili16
mili16 mili16
  • 13-07-2017
  • Mathematics
contestada

Help on this question please

Help on this question please class=

Respuesta :

jdoe0001 jdoe0001
  • 13-07-2017
[tex]\bf \textit{using the pythagorean theorem}\\\\ c^2=a^2+b^2\qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ -------\\ c=x\\ a=7\\ b=10 \end{cases}\implies x^2=7^2+10^2 \\\\\\ x=\sqrt{7^2+10^2}[/tex]

and surely you know how much that is.
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