Respuesta :

scarrockminecr
perpendicular lines have negative reciprocal slopes:
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slope of q = -1/(1/5)
slope of q = -1*(5/1)
slope of q = -5
For two lines to be perpendicular, their slopes are defined to be negative reciprocals of each other; that is [tex]m_1 \cdot m_2 = -1[/tex]

Let [tex]m_1 = \frac{1}{5}[/tex]
[tex]\frac{1}{5} \cdot m_2 = -1[/tex]
[tex]m_2 = -\frac{1}{\frac{1}{5}}[/tex]
[tex]m_2= -5[/tex]

Thus, the slope of line q must be -5.

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