VishvC764716 VishvC764716
  • 03-11-2022
  • Mathematics
contestada

2) f(n) = 10.2^n at n=5

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SherD290999 SherD290999
  • 03-11-2022

F(n) = 10 . 2^n

To calculate F(5) , replace n by 5, and solve:

F(5)= 10 . 2^5 = 10 . 32 = 320

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