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  • 14-02-2017
  • Mathematics
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How many and what type of solutions does the equation have? 2k² = 9 + 3k

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Аноним Аноним
  • 14-02-2017
2k² = 9 + 3k 
⇒ 2k² - 9 - 3k = 0
⇒ 2k² - 3k -9 = 0

b² - 4ac = 3² - 4*2*(-9) = 81>0

It has 2 real roots.
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