The 6th term of the sequence is 4
How to determine the 6th term?
The given parameters are:
a1 = -4096
a4 = 64
The nth term of the sequence is:
a(n) = a1 * r^(n-1)
So, we have:
a4 = a1 * r^3
This gives
r^3 = a4/a1
Substitute the known values
r^3 = 64/-4096
Evaluate
r^3 = -1/64
Take the cube roots
r = -1/4
The 6th term is
a(6) =a1 * r^5
This gives
a(6) = -4096 * (-1/4)^5
Evaluate
a(6) = 4
Hence, the 6th term of the sequence is 4
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