adewusijohn149 adewusijohn149
  • 11-07-2022
  • Mathematics
contestada

if ABC is a isosceles triangle with sides(2a+b)cm, (6a+2b+1)cm and a base of 4a cm, if it's perimeter is 28 find sides​

Respuesta :

2200243 2200243
  • 11-07-2022

Answer:

a=1.5, b= 3

Step-by-step explanation:

sum of all sides will give us perimeter. Therefore

2a+b+6a+2b+1+4a=28

12a+3b+1=28

12a+3b=27....eqn1

since t two sides of this isosceles triangle are equal:

2a+b=4a

2a=b

[tex]a=\frac{b}{2}[/tex]

substituting [tex]\frac{b}{2}[/tex][tex].[/tex] in the first equation whenever we encounter a we will have:

[tex]12(\frac{b}{2})+3b=27\\[/tex]

6b+3b=27

9b=27

b=3

therefore [tex]a= \frac{b}{2} =\frac{3}{2} =1\frac{1}{2} or 1.5[/tex]

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