martinaus0
martinaus0 martinaus0
  • 13-06-2022
  • Mathematics
contestada

integral pls i couldnt​

integral pls i couldnt class=

Respuesta :

LammettHash
LammettHash LammettHash
  • 13-06-2022

Simplify the integrand:

[tex]\dfrac{4x^4 + 3x^2 + 5x}{x^2} = 4x^2 + 3 + \dfrac5x[/tex]

Now integrate one term at a time.

[tex]\displaystyle \int 4x^2 \, dx = \frac43 x^3 + C[/tex]

[tex]\displaystyle \int 3 \, dx = 3x + C[/tex]

[tex]\displaystyle \int \frac5x \, dx = 5 \ln|x| + C[/tex]

Putting everything together,

[tex]\displaystyle \int \frac{4x^4 + 3x^2 + 5x}{x^2} \, dx = \int \left(4x^2 + 3 + \frac5x\right) \, dx = \boxed{\frac43 x^3 + 3x + 5 \ln|x| + C}[/tex]

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