Answer:
BC ≈ 2.598076211
Step-by-step explanation:
Given [tex]\frac{AB}{3} = sinC[/tex]
That means side AC = 3
Let's use [tex]sinA[/tex] to find BC
[tex]sinA = sin60 = \frac{BC}{AC} = \frac{BC}{3}[/tex]
[tex]BC = 3sin60[/tex]
