[tex]\boxed{\sf tan\theta=\dfrac{Perpendicular}{Base}}[/tex]
- Perpendicular=27.8ft
- Base=19.6ft
Now
[tex]\\ \tt\hookrightarrow tanx=\dfrac{27.8}{19.6}[/tex]
[tex]\\ \tt\hookrightarrow tanx=\dfrac{13.9}{9.8}[/tex]
[tex]\\ \tt\hookrightarrow tanx=1.418[/tex]
[tex]\\ \tt\hookrightarrow \underline{\boxed{\bf tanx=1.42}}[/tex]
Value of x
[tex]\\ \tt\hookrightarrow x=tan^{-1}(1.42)[/tex]
[tex]\\ \tt\hookrightarrow x=54.8°[/tex]
Hope It helps
