18rmistry 18rmistry
  • 15-01-2022
  • Mathematics
contestada

Solve the equation
4(22–3x) = 256

Solve the equation 4223x 256 class=

Respuesta :

bladeyboi bladeyboi
  • 15-01-2022

Answer:

x = -1, x = 4

Step-by-step explanation:

Attachment shows work. Sorry if it's a little messy; I don't have an option to scroll on the app. You can ask me about it, though.

Ver imagen bladeyboi
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yonas17 yonas17
  • 15-01-2022
4^(x^2-3x)=256
First
256=4^4
4^(x^2-3x)= 4^4 a^x=a^y x=y
X^2-3x=4
X^2-3x-4=0 by using quadratic formula
x = (-b ± √(b2 − 4ac))/(2a)
=-(-3) ±√((-3)2 − 4(1 )(-4)/(2(1))
= (3 ±√(9 + 16))/2
= (3 ±√(25))/2
= (3 ±5)/2
X= 4 or -1
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