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14-01-2022
Physics

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Now find what k value would be needed to stretch the spring 0.25 m at a force value of 25 N.

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14-01-2022

Hi there!

[tex]\boxed{k = 100N/m}[/tex]

Using Hooke's Law:

[tex]F = kx[/tex]

F = force (N)

k = Spring Constant (N/m)

x = displacement from equilibrium (m)

Plug in the given values:

25 = k(0.25)

25 = 0.25k

Solve for k:

25/0.25 = k

k = 100 N/m

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