[tex]\dfrac x6 - \dfrac y3 =1\\\\\\\implies \dfrac x6 - \dfrac{2y}6 = 1\\\\\\\implies \dfrac{x-2y}6 =1\\\\\\\implies x -2y =6\\\\\\\implies x =6+2y\\\\\\\implies x = 2(3 +y)[/tex]
