Answer:
-52, -50, -48, -46
Step-by-step explanation:
Let the first even integer be a.
The second even integer is a + 2.
The third even integer is a + 2 + 2 = a + 4.
The fourth even integer is a + 4 + 2 = a+ 6
The sum of 4 consecutive even integers = -196
-196 = a + (a + 2) + (a + 4) + (a + 6)
-196 = 4a + 12
-208 = 4a
a = -52
The second even integer = -52 + 2 = -50
The third even integer = -52 + 4 = -48
The fourth even integer = -52 + 6 = -46
