JesusTrrsDeLosLlanos JesusTrrsDeLosLlanos
  • 13-12-2016
  • Mathematics
contestada

The slope of a line is -1/5, and the y-intercept is 5. What is the equation of the line written in general form? x - 5y - 25 = 0 x - 5y - 5 = 0 x + 5y - 25 = 0

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Аноним Аноним
  • 13-12-2016
answer is x + 5y - 25 = 0

y - 5 = -1/5 (x-0)
y - 5 = -1/5x
-5y + 25 = x
x + 5y - 25 = 0
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agaue agaue
  • 30-11-2019

x + 5 y - 25 = 0

Option C is the correct answer.

Step-by-step explanation:

Equation of straight line is given by y = mx + c

    Slope of line , m = -1/5

    y- intercept, c = 5

Substituting

                      [tex]y=mx+c\\\\y=\frac{-1}{5}x+5\\\\y=\frac{-x+25}{5}\\\\5y=-x+25\\\\x+5y-25=0[/tex]

x + 5 y - 25 = 0

Option C is the correct answer.

Answer Link

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