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  • 14-06-2021
  • Mathematics
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FIND THE CENTER AND THE RADIUS OF THIS EQUATION: (X+4)^2+ (Y-3)^2 =16

FIND THE CENTER AND THE RADIUS OF THIS EQUATION X42 Y32 16 class=

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mathmate
mathmate mathmate
  • 14-06-2021

Answer:

centre = (-4,3) and radius 4

Step-by-step explanation:

Standard equation for a circle :

(x-a)² + (y-b)² = r²

for a circle with radius r centred at (a,b).

(X+4)^2+ (Y-3)^2 =16

(x - (-4))² + (y-3)² = 4²

Therefore centre (a,b) = (-4,3) and radius 4

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