Answer:
4
Explanation:
Applying,
pH = 14-pOH.................... Equation 1
But,
pOH = -log(OH⁻)
Where OH⁻ = Hydroxyl ion concentration of NaOH.
From the question,
Given: OH⁻ = (1×10⁻¹⁰) M
Substitute these values into equation 1
pH = 14-log((1×10⁻¹⁰)
pH = 14-10
pH = 4
Hence the pH of NaOH with a molarity of 1.0 x 10-10M = 4
