Respuesta :

Answer:

[tex]\sqrt{10}[/tex]/10

Step-by-step explanation:

cos is adjacent side/hypotenuse

you need to find the hypotenuse

Let h = length of hypotenuse

[tex]6^{2} + 18^{2} = h^{2}[/tex]

[tex]h^{2}[/tex] = 36 + 324 = 360

h = [tex]\sqrt{360}[/tex] = 6[tex]\sqrt{10}[/tex]

cos (theta) = 6/6[tex]\sqrt{10}[/tex] = 1/[tex]\sqrt{10}[/tex] = [tex]\sqrt{10}[/tex]/10