Answer:
12 N
Explanation:
Given that a 12 kg object's velocity changes from 5 m/s to 10 m/s in 5 s, what amount of force was applied to increase the speed of the object?
Solution
M = 12 kg
T = 5 s
The formula to use will be
F = ma
Where
Acceleration a = change in velocity/ time
Acceleration a = ( 10 - 5 ) / 5
Acceleration a = 5 / 5
Acceleration a = 1 m/s^2
Substitutes a into the formula above
F = ma
F = 12 × 1
F = 12 N
Therefore, the amount of force applied to increase the speed of the object is 12 N.
