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  • 13-04-2021
  • Mathematics
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find the inverse f(x) = 3х^2 - |

Respuesta :

786winkoaung
786winkoaung 786winkoaung
  • 13-04-2021

Answer:

[tex]f^{-1}[/tex]=[tex]\frac{\sqrt{3(x+1)} }{3}[/tex]

Step-by-step explanation:

f(x) = 3[tex]x^{2}[/tex] - |

Let y= 3[tex]x^{2}[/tex]-1

Both side -1

y+1=3[tex]x^{2}[/tex]  

[tex]x^{2}[/tex]=    [tex]\frac{\sqrt{3(y+1)} }{3}[/tex]

x=  [tex]\frac{\sqrt{3(y+1)} }{3}[/tex]

[tex]f^{-1}[/tex]=[tex]\frac{\sqrt{3(x+1)} }{3}[/tex]

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