Answer:
RQ = RS = 3
Step-by-step explanation:
Since RQ and RS are radii of the circle then they are congruent
let RQ and RS be x , then
Using Pythagoras' identity in right triangle QRS
x² + x² = (3[tex]\sqrt{2}[/tex] )²
2x² = 18 ( divide both sides by 2 )
x² = 9 ( take the square root of both sides )
x = [tex]\sqrt{9}[/tex] = 3
Thus RQ = RS = 3
