Answer:
(x + 1)(x + 3)eˣ
Step-by-step explanation:
Since f(x) = (x + 1)²eˣ
df(x)/dx = d[(x + 1)²eˣ]/dx
By the product rule, duv/dx = udv/dx + vdu/dx
where u = (x + 1)² and v = eˣ
So, df(x)/dx = d[(x + 1)²eˣ]/dx
= (x + 1)²deˣ/dx + eˣd(x + 1)²/dx
= (x + 1)²eˣ + eˣd(x + 1)²/d(x + 1) × d(x + 1)/dx (by the chain-rule dy/dx = dy/du × du/dx)
= (x + 1)²eˣ + eˣ[2(x + 1) × 1]
= (x + 1)²eˣ + 2eˣ(x + 1)
= (x + 1)eˣ(x + 1 + 2)
= (x + 1)eˣ(x + 3)
= (x + 1)(x + 3)eˣ
