Respuesta :

maacastrobr

Answer:

40.1 g

Explanation:

The balanced equation is:

  • Ca(ClO₃)₂ → CaCl₂ + 3O₂

First we convert 86.5 g of calcium chlorate into moles, using its molar mass:

  • 86.5 g Ca(ClO₃)₂ ÷ 206.98 g/mol = 0.418 mol Ca(ClO₃)₂

Then we convert Ca(ClO₃)₂ moles into O₂ moles, using the stoichiometric coefficients of the balanced reaction:

  • 0.418 mol Ca(ClO₃)₂ * [tex]\frac{3molO_2}{1molCa(ClO_3)_2}[/tex] = 1.254 mol O₂

Finally we convert O₂ moles into grams:

  • 1.25 mol O₂ * 32 g/mol = 40.1 g O₂

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