Answer:
Step-by-step explanation:
[tex]\frac{15}{4} =\frac{AE}{AC} =\frac{AC+7}{AC} =1+\frac{7}{AC} \\\frac{7}{AC} =\frac{15}{4} -1=\frac{15-4}{4} =\frac{11}{4} \\11AC=28\\AC=\frac{28}{11}\\\tan~A=\frac{4}{AC} =\frac{4}{\frac{28}{11} } =\frac{4 \times 11}{28} =\frac{11}{7} \\A=\tan^{-1}(\frac{11}{7} ) \approx 57.5^\circ[/tex]
