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13-03-2021
Mathematics

contestada

(8x^2+3xy-20y^2)-(-4x^2+3xy+20y^2)

Respuesta :

13-03-2021

Step-by-step explanation:

(8x² + 3xy -20y²)-(-4x²+3xy+20y²)

= 8x² + 3xy -20y² + 4x² -3xy - 20y²

= 8x² + 4x² + 3xy - 3xy -20y² -20y²

= 12x² - 40y²

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