Answer:
43.83 N
Explanation:
Given that,
The mass of an object, m = 34.4 kg
The coefficients of static and kinetic frictions for plastic on wood are 0.53 and 0.40, respectively.
The force of static friction,
[tex]F_s=\mu_smg\\\\F_s=0.53\times 34.4\times 9.8\\\\F_s=178.67\ N[/tex]
The force of kinetic friction,
[tex]F_k=\mu_kmg\\\\F_k=0.40\times 34.4\times 9.8\\\\F_k=134.84\ N[/tex]
Net force acting on the object is :
F = 178.67-134.84
= 43.83 N
Hence, this is the required solution.
