dariakrylov1 dariakrylov1
  • 15-01-2021
  • Mathematics
contestada

[tex](\frac{3x^-3y^4}{5x^6y^7 })^-2[/tex]

Respuesta :

sqdancefan
sqdancefan sqdancefan
  • 15-01-2021

9514 1404 393

Answer:

  (25/9)x^18·y^6

Step-by-step explanation:

Maybe you want this simplified.

The appropriate rules of exponents are ...

  (a^b)/(a^c) = a^(b-c)

  (a^b)^c = a^(bc)

__

  [tex]\left(\dfrac{3x^{-3}y^4}{5x^6y^7}\right)^{-2}=\left(\dfrac{3x^{-3-6}y^{4-7}}{5}\right)^{-2}=\dfrac{3^{-2}}{5^{-2}}\cdot x^{(-2)(-9)}y^{(-2)(-3)}\\\\=\boxed{\dfrac{25}{9}x^{18}y^{6}}[/tex]

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