Respuesta :

SvetlanaM

Answer:  [tex]\dfrac{y^{2} }{2}[/tex]

Step-by-step explanation:

[tex]2^{x} =y\\\\8(4^{x-2} )=8 \cdot \dfrac{4^{x} }{4^{2} } =8 \cdot \dfrac{(2^{x})^{2} }{16 } =8 \cdot \dfrac{(2^{x})^{2} }{8 \cdot 2 } =\dfrac{y^{2} }{2}[/tex]

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