JelTa6nda9elvei
JelTa6nda9elvei JelTa6nda9elvei
  • 12-09-2016
  • Chemistry
contestada

how many moles of naoh are present in 29.0 ml of 0.290 m naoh?

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Willchemistry
Willchemistry Willchemistry
  • 13-09-2016
29.0 mL in liters:

29.0 / 1000 => 0.029 L

n = M x V

n = 0.290 x 0.029

n = 0.00841 moles of NaOH

hope this helps!
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