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  • 13-08-2020
  • Mathematics
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2.Show that: (sinΘ + cosΘ)^2 + (sinΘ - cosΘ)^2 = 2

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bekkarmahdi702
bekkarmahdi702 bekkarmahdi702
  • 13-08-2020

Answer:

Below

Step-by-step explanation:

● A = (sinO +cosO)^2 +(sinO -cosO)^2

●A = sin^2(O) +2×sinO×cosO +cos^2(O)+sin^2O-2×cosO×sinO +cos^2(O)

● A = sin^2(O) +cos^2(O)+sin^2(O)+cos^2(O)

We khow that cos^2 x + sin^2 x = 1

● A = 1+1

● A=2

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