Answer: x < 3
Step-by-step explanation:
4(x + 3) < 3(x + 5)
4x + 12 < 3x + 15 Distributed
x + 12 < 15 Subtracted 3x from both sides
x < 3 Subtracted 12 from both sides
Answer:
4x^2+9x-15<0
x.4(x+3)<3(x+5)
(4x)(x+3)<3x+3x5
(4x)(x+3)<3x+15
4xx+4x.3<3x+15
4x^1+1+4x3x<3x+15
4x^2+12x<3x+15
(4x^2+12x)+(-3x-15)<(3x+15)+(-3x-15x)
4x^2+9x-15<3x-3x+15-15
