httydhussinytsper121 httydhussinytsper121
  • 11-07-2020
  • Mathematics
contestada

h(x)=1/8x^3-x^2 What is the average rate of change of h over the interval -2≤x≤2?

Respuesta :

jimrgrant1 jimrgrant1
  • 11-07-2020

Answer:

[tex]\frac{1}{2}[/tex]

Step-by-step explanation:

The average rate of change of h(x) in the closed interval [ a, b ] is

[tex]\frac{h(b)-h(a)}{b-a}[/tex]

Here [ a , b ] = (- 2, 2 ] , thus

h(b) = h(2) = [tex]\frac{1}{8}[/tex] (2)³ - 2² = 1 - 4 = - 3

h(a) = h(- 2) = [tex]\frac{1}{8}[/tex] (- 2)³ - (- 2)² = - 1 - 4 = - 5 , thus

average rate of change = [tex]\frac{-3-(-5)}{2-(-2)}[/tex] = [tex]\frac{2}{4}[/tex] = [tex]\frac{1}{2}[/tex]

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