aawinterbabyp7nk4j aawinterbabyp7nk4j
  • 15-06-2020
  • Mathematics
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Solve the equation using the quadratic formula. 3x^2-18=-6 a) x = ± 6 b)x = ± 2 c)x = 6 d)x = 2

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z31415 z31415
  • 15-06-2020

Answer: B x=+-2

Step-by-step explanation:

The Quadratic formula is -b+-[tex]-b+-\sqrt{(b^{2} -4ac)} /2a[/tex]

First make everything equal to 0

[tex]3x^2-18+6=0[/tex]

Then Simplify

[tex]3x^2-12=0[/tex]

Now use the formula where a=3, b=0, and c=-12

[tex]0+-\sqrt{0^2-4(3)(-12)[/tex]  divided by 2(3)

[tex]0+-\sqrt{0-(-144)}/6[/tex]

[tex]\frac{0+-12}{6}[/tex]

then we get 12/6 and -12/6 which simplified is +-2

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