Answer:
[tex]-1\pm\dfrac{\sqrt{14}}{2}[/tex]
Step-by-step explanation:
[tex]2x^2+4x-5=0[/tex]
Using the quadratic formula:
[tex]x=\dfrac{-4\pm \sqrt{16+40}}{4}=-1\pm\dfrac{\sqrt{14}}{2}[/tex]
Hope this helps!
