Answer:
Step-by-step explanation:
[tex]\frac{x(x+1)}{(x-2)(x+1)} + \frac{(x-1)(x-2)}{(x+1)(x-2)} =-\frac{(x-2)(x+1)}{(x-2)(x+1)}[/tex]
These 3 terms have meme (x-2)(x+1), so we have:
x(x+1) +(x-1)(x-2) = - (x-2)(x+1)
Or x^2 +x +x^2 -3x +2 = -x^2 +x +2
and 3x^2 -3x =0
The factor: 3x( x-1) =0
and we have x= 0 or x-1=0, x=1
The 2 solution: 0 and -1.
Hope that useful for you.
