Answer:
[tex]\sin^{-1}{\frac{5}{11}}[/tex] or approximately 27.04°
Step-by-step explanation:
From basic trig ratios, we know that [tex]\sin{M}=\frac{opposite}{hypotenuse} =\frac{NO}{MO}=\frac{5}{11}[/tex]. We can take the inverse sine of both sides to "undo" the sine function and get us back the measure of ∠M:
[tex]\sin^{-1}(\sin{M})=\sin^{-1}\frac{5}{11} \approx 27.04^{\circ}[/tex]
