deanawahkuna
deanawahkuna deanawahkuna
  • 13-04-2020
  • Mathematics
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Special right triangles
Help me find s

Special right triangles Help me find s class=

Respuesta :

jimrgrant1 jimrgrant1
  • 13-04-2020

Answer:

s = 3[tex]\sqrt{3}[/tex]

Step-by-step explanation:

Using the cosine ratio in the right triangle and the exact value

cos30° = [tex]\frac{\sqrt{3} }{2}[/tex]

cos30° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{s}{6}[/tex] = [tex]\frac{\sqrt{3} }{2}[/tex] ( cross- multiply )

2s = 6[tex]\sqrt{3}[/tex] ( divide both sides by 2 )

s = 3[tex]\sqrt{3}[/tex]

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