Answer:
If f(x) = 1 – x then, value of |f(i)| is:
√2
Step-by-step explanation:
f(x) = 1 – x
Then, f(i) = 1 - i
We know that if f(z)=x+iy then, |f(z)|=[tex]\sqrt{x^2+y^2}[/tex]
Hence, |f(i)| = [tex]\sqrt{1^2+(-1)^2}[/tex]
= [tex]\sqrt{1+1}[/tex]
= √2
Hence, if f(x) = 1 – x then, value of |f(i)| is:
√2
