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Describe how you would prepare 2.44 kg of an aqueous solution that is 16.3% KOH by mass.
Describe how you would prepare 2.44 of an aqueous solution that is 16.3% by mass.
0.163 kg KOH. Add 0.163 kg KOH to 2.277 kg water.
2.44 kg solution x 0.163 = 0.40 kg KOH. Add 0.40 kg KOH to 2.84 kg water.
0.163 kg KOH. Add 0.163 kg KOH to 2.603 kg water.
2.44 kg solution x 0.163 = 0.40 kg KOH. Add 0.40 kg KOH to 2.04 kg water.
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Answer:

  • Add 0.40 kg KOH to 2.04 kg water.

Explanation:

The formula for mass percentage is:

  • % (w/w) = (mass of solute / mass of solution) × 100

The data are:

  • mass of solution:  2.44 kg
  • % (w/w) = 16.3

Substitute and solve:

  • 16.3 = ( x / 2.44kg ) × 100
  • x = 16.3 ×2.44kg / 100 =  0.39772kg ≈ 0.40kg

Then, you will need to use 0.40kg of KOH and the amount of water needed to complete 2.44 kg of solution:

  • water = 2.44kg - 0.40kg = 2.04kg

Conclusion

  • Add 0.40kg of KOH to 2.04 kg of water.

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