Seudónimo Seudónimo
  • 14-10-2014
  • Mathematics
contestada

How do I solve more complicated equations e.g
3 (4a x3) = 4

Respuesta :

xXxGirxXx
xXxGirxXx xXxGirxXx
  • 14-10-2014
3 (4a × 3) = 4     :First, distribute (Multiply the 3 times the 4a and the other 3)

12a × 9 = 4         :Then, divide the whole equation by 9

12a = 4/9             :Then, divide the whole equation by 12

a = 1/27          

(At least, that what I hoped your equation said at the beginning xD)


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kate200468
kate200468 kate200468
  • 14-10-2014
[tex]3 (4a\cdot 3) = 4\\3\cdot12a=4\\36a=4\ /:36\\\\a= \frac{\big{4}}{\big{36}} \\\\ a= \frac{\big{4:4}}{\big{36:4}} \\\\ a= \frac{\big{1}}{\big{9}}[/tex]
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