Nnamdi222 Nnamdi222
  • 14-12-2019
  • Mathematics
contestada

fine the 25th term of an arithmetic progression 12,16,20,24,
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Respuesta :

jimrgrant1 jimrgrant1
  • 14-12-2019

Answer:

108

Step-by-step explanation:

The n th term of an arithmetic sequence is

[tex]a_{n}[/tex] = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 12 and d = 16 - 12 = 4, thus

[tex]a_{25}[/tex] = 12 + (24 × 4) = 12 + 96 = 108

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azizaziz19014 azizaziz19014
  • 14-12-2019
108. As you can see, it is going up by 4 each time. So 12 being the 1st term, 16 being the 2nd, and so on. Keep adding 4 until you reach the 25th term, which is 108
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