Answer:
The acceleration of the bullet is 212.12 m/s²
Explanation:
Given that,
Force = 1.4 N
Mass = 6.6 g
We need to calculate the acceleration
Using newton's second law
[tex]F=ma[/tex]
[tex]a=\dfrac{F}{m}[/tex]
Where, F = force
m = mass
Put the value into the formula
[tex]a=\dfrac{1.4 }{6.6\times10^{-3}}[/tex]
[tex]a=212.12\ m/s^2[/tex]
Hence, The acceleration of the bullet is 212.12 m/s²
