swaggyd9782 swaggyd9782
  • 13-09-2019
  • Engineering
contestada

If an elevator is to raise a 5000 lb a height of 30 ft in 320 seconds, what horsepower motor would be required?

Respuesta :

aristeus aristeus
  • 19-09-2019

Answer:

Force will be equal to 0.08522 horsepower

Explanation:

We given weight of elevator = 5000 lb

Height of the elevator = 30 ft

Time t = 320 sec

We have to calculate the power in horsepower

For let first find power in lb-ft/sec

So power in lb-ft/sec [tex]=\frac{5000lb\times 30ft}{320sec}=46.875lb-ft/sec[/tex]

Now we know that 1 horsepower = 550 lb-ft/sec

So 46.785 lb-ft/sec = [tex]\frac{46.875}{550}=0.08522horsepower[/tex]

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