Answer:
P₁ = 192 W and P₂ = 384 W
Explanation:
It is given that,
Resistor 1, [tex]R_1=12\ \Omega[/tex]
Resistor 2, [tex]R_1=6\ \Omega[/tex]
Voltage, V = 48 V
Power dissipated by resistor 1 is given by :
[tex]P_1=\dfrac{V^2}{R_1}[/tex]
[tex]P_1=\dfrac{(48)^2}{12}[/tex]
P₁ = 192 watts
Power dissipated by resistor 2 is given by :
[tex]P_2=\dfrac{V^2}{R_1}[/tex]
[tex]P_2=\dfrac{(48)^2}{6}[/tex]
P₂ = 384 watts
So, the power dissipated by both the resistors is 192 watts and 384 watts respectively. Hence, this is the required solution.
